In the movie Joker, when killing three white collars in a subway, Arthur fires eight rounds out of his 38 revolver that holds five or six bullets without reloading.

I doubt it is a mistake, why does this happen?

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    This could be a mistake, or it could be an indication that this is yet another delusion. IMHO it is impossible to answer questions like this about "Joker", since the entire movie is one massive case of "unreliable narrator" / "it is all in his head". – BCdotWEB Oct 14 '19 at 12:12
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    @BCdotWEB sounds like a potential answer rather than a reason to downvote. – Ankit Sharma Oct 14 '19 at 13:19
  • @AnkitSharma I haven't seen the movie, so I can only go by Reddit threads, which seem to suggest that the movie explicitly mentions the bullet limit (and even shows it) and that the movie even points out that Arthur had only access to a limited amount of ammo. But since I haven't seen the movie, I cannot judge whether this is really so explicit and thus whether this discrepancy in possible rounds is merely a mistake or a signal to the viewer. – BCdotWEB Oct 14 '19 at 16:14
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    Is it explicit in the film that this is a 5- or 6-shot revolver? There are 8-shot revolvers available; for instance: smith-wesson.com/firearms/performance-center-model-327 – chili555 Oct 18 '19 at 2:05

I doubt it's a mistake. There are close-up shots of the gun where you can clearly see that it's a 5 or 6 shot revolver. In fact, IMFDB identifies it specifically as a Smith & Wesson Model 36, which holds five shots.

I think the most likely explanation is that Arthur is an unreliable narrator. Arthur suffers from various unspecified mental disorders, and several scenes are shown to be in his imagination, most obviously his appearance in the audience of the talk show, and his relationship with Sophie. Scenes like the subway shooting aren't explicitly shown to be imagined, but subtle details like the number of shots fired are clues that what we're seeing may not be as they actually happened (if they did at all).

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