In the movie Joker, when killing three white collars in a subway, Arthur fires eight rounds out of his 38 revolver that holds five or six bullets without reloading.
I doubt it is a mistake, why does this happen?
In the movie Joker, when killing three white collars in a subway, Arthur fires eight rounds out of his 38 revolver that holds five or six bullets without reloading.
I doubt it is a mistake, why does this happen?
I doubt it's a mistake. There are close-up shots of the gun where you can clearly see that it's a 5 or 6 shot revolver. In fact, IMFDB identifies it specifically as a Smith & Wesson Model 36, which holds five shots.
I think the most likely explanation is that Arthur is an unreliable narrator. Arthur suffers from various unspecified mental disorders, and several scenes are shown to be in his imagination, most obviously his appearance in the audience of the talk show, and his relationship with Sophie. Scenes like the subway shooting aren't explicitly shown to be imagined, but subtle details like the number of shots fired are clues that what we're seeing may not be as they actually happened (if they did at all).
The screenplay lists it as a...
".38 snub-nosed revolver"
...without going into any particular detail about what make or model the gun is. When we see him fire it on the subway, he fires seven shots in total. The script described him 'emptying the gun' into his victims without reloading.
BLAM! The third guy falls, tumbling down the stairs. Arthur walks over to the body and empties the chamber— BLAM! BLAM! … BLAM! He's got nothing left.
I rewatched the movie recently with this in mind. I noticed after killing the first 2 guys, he tries to kill the 3rd but the gun clicks (it's really subtle). So I'm guessing he reloaded a few bullets to finish the last guy off.